JKPSC Recruitment 2019, JKPSC Recruitment, JKPSC Jobs

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JKPSC Recruitment 2019, JKPSC Recruitment, JKPSC Jobs

Job Description

Jammu and Kashmir Public Service Commission under the government of India has declared a new notification for eligible candidates. JKPSC revealed the placements of Veterinary Assistant Surgeon vacancies. JKPSC are revealed the total placements of 200. Nowadays so many candidates are searching for job. This is a good opportunity. So utilize this chance. Who have been completed for graduation with attractive marks. For more details of information please scroll down….

JKPSC Vacancy Details

Name of the Post Veterinary Assistant Surgeon
Total Vacancies 200 posts
Qualification GRADUATION
Salary 52,700 – 16,6700
Location of the Job Jammu and Kashmir

JKPSC Educational Details

  • The candidates should have passed bachelor’s Degree in Veterinary Sciences and Animal husbandry

JKPSC Age Criteria

Age Limit as on 01.01.2018

  • Minimum age limit is: 18 years
  • Maximum age limit is 40 years
  • PH candidates: 42 years
  • SC, ST, ALC, SLC, RBA candidates age limit is 43 years
  • EX-SM age limit is:48 years

Application Fee

  • OBC, General: 400/-
  • ST, SC, Ex, SM and PWD: 200/-

Selection Procedure

  • Written Exam
  • Interview

JKPSC Applying Process

  • Click the official website jkpsc.nic.in
  • Homepage will appear
  • Search for JKPSC Recruitment 2019 Notification for Veterinary Assistant Surgeon vacancies
  • Read the application carefully
  • If you interested and apply the online
  • Scanned the educational documents as per notification specification
  • Scanned the signature/thumb as per notification specification
  • Scanned the passport size photo as per notification specification
  • Pay the required fee
  • Click the submit button and take a printout of application form future use

JKPSC Important Dates

  • Online registration starting date: 01.01.2019
  • Online registration last date: 23.01.2019
  • Written Exam Date: 17.02.2019

Apply Online

http://www.jkpsc.nic.in/Pages/Applicant/Jobs.aspx?id=1

 

 

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